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[Enhance] World rank score mechanism

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- Adjust world rank mechanism to be closer to the official one.

Note: You need to refresh rating in web admin backend after updating, and the users need to get a better or new score to refresh world rank.
This commit is contained in:
Lost-MSth
2024-06-14 16:06:26 +08:00
parent 338f6579aa
commit 2a08c9cd14
11 changed files with 137 additions and 30 deletions
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18
latest version/core/user.py
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@@ -528,7 +528,11 @@ class UserInfo(User):
'world_mode_locked_end_ts': self.world_mode_locked_end_ts,
'locked_char_ids': [], # [1]
'user_missions': UserMissionList(self.c, self).select_all().to_dict_list(),
'pick_ticket': self.pick_ticket
'pick_ticket': self.pick_ticket,
# 'custom_banner': 'online_banner_2024_06',
# 'subscription_multiplier': 114,
# 'memory_boost_ticket': 5,
}
def from_list(self, x: list) -> 'UserInfo':
@@ -648,8 +652,8 @@ class UserInfo(User):
'''用户世界排名，如果超过设定最大值，返回0'''
if self.world_rank_score is None:
self.select_user_one_column('world_rank_score', 0)
if self.world_rank_score is None:
return 0
if not self.world_rank_score:
return 0
self.c.execute(
'''select count(*) from user where world_rank_score > ?''', (self.world_rank_score,))
@@ -665,14 +669,14 @@ class UserInfo(User):
self.c.execute(
'''
with user_scores as (
select song_id, difficulty, score from best_score where user_id = ? and difficulty in (2, 3, 4)
select song_id, difficulty, score_v2 from best_score where user_id = ? and difficulty in (2, 3, 4)
)
select sum(a) from(
select sum(score) as a from user_scores where difficulty = 2 and song_id in (select song_id from chart where rating_ftr > 0)
select sum(score_v2) as a from user_scores where difficulty = 2 and song_id in (select song_id from chart where rating_ftr > 0)
union
select sum(score) as a from user_scores where difficulty = 3 and song_id in (select song_id from chart where rating_byn > 0)
select sum(score_v2) as a from user_scores where difficulty = 3 and song_id in (select song_id from chart where rating_byn > 0)
union
select sum(score) as a from user_scores where difficulty = 4 and song_id in (select song_id from chart where rating_etr > 0)
select sum(score_v2) as a from user_scores where difficulty = 4 and song_id in (select song_id from chart where rating_etr > 0)
)
''',
(self.user_id,)