[Enhance] Recent 30

- Update Recent 30 mechanism.
- Alter Recent 30 table structure.

Note:
1. This is a TEST version. Maybe there are many bugs.
2. This special version is a line of demarcation.
This commit is contained in:
Lost-MSth
2024-04-30 00:27:23 +08:00
parent efedd96908
commit 5c539bdf59
10 changed files with 201 additions and 215 deletions

View File

@@ -1,5 +1,7 @@
import time
from core.score import Potential
def get_user_score(c, user_id, limit=-1, offset=0):
# 返回用户的所有歌曲数据,带排名,返回字典列表
@@ -74,37 +76,3 @@ def get_user(c, user_id):
}
return r
def get_user_recent30(c, user_id):
# 获取玩家recent30信息并计算recent10的ptt返回字典列表和一个值
c.execute('''select * from recent30 where user_id=:a''', {'a': user_id})
sumr = 0
x = c.fetchone()
r = []
if x is not None:
r30 = []
s30 = []
for i in range(1, 61, 2):
if x[i] is not None:
r30.append(float(x[i]))
s30.append(x[i+1])
else:
r30.append(0)
s30.append('')
r30, s30 = (list(t) for t in zip(*sorted(zip(r30, s30), reverse=True)))
songs = []
i = 0
while len(songs) < 10 and i <= 29 and s30[i] != '' and s30[i] is not None:
if s30[i] not in songs:
sumr += r30[i]
songs.append(s30[i])
i += 1
for i in range(0, 30):
if s30[i]:
r.append({
'song_id': s30[i][:-1],
'difficulty': int(s30[i][-1]),
'rating': r30[i]
})
return r, sumr / 10