75 lines
2.3 KiB
Python
75 lines
2.3 KiB
Python
"""
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在线状态维护服务
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此模块提供在游玩状态下维护用户在线状态的功能，
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解决游玩时显示离线的问题。
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"""
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from __future__ import annotations
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import asyncio
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from app.dependencies.database import get_redis
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from app.log import logger
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from app.router.v2.stats import REDIS_PLAYING_USERS_KEY, _redis_exec, get_redis_message
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async def maintain_playing_users_online_status():
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"""
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维护正在游玩用户的在线状态
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定期刷新正在游玩用户的metadata在线标记，
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确保他们在游玩过程中显示为在线状态。
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"""
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redis_sync = get_redis_message()
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redis_async = get_redis()
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try:
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# 获取所有正在游玩的用户
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playing_users = await _redis_exec(redis_sync.smembers, REDIS_PLAYING_USERS_KEY)
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if not playing_users:
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return
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logger.debug(f"Maintaining online status for {len(playing_users)} playing users")
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# 为每个游玩用户刷新metadata在线标记
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for user_id in playing_users:
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user_id_str = user_id.decode() if isinstance(user_id, bytes) else str(user_id)
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metadata_key = f"metadata:online:{user_id_str}"
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# 设置或刷新metadata在线标记，过期时间为1小时
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await redis_async.set(metadata_key, "playing", ex=3600)
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logger.debug(f"Updated metadata online status for {len(playing_users)} playing users")
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except Exception as e:
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logger.error(f"Error maintaining playing users online status: {e}")
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async def start_online_status_maintenance_task():
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"""
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启动在线状态维护任务
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每5分钟运行一次维护任务，确保游玩用户保持在线状态
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"""
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logger.info("Starting online status maintenance task")
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while True:
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try:
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await maintain_playing_users_online_status()
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# 每5分钟运行一次
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await asyncio.sleep(300)
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except Exception as e:
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logger.error(f"Error in online status maintenance task: {e}")
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# 出错后等待30秒再重试
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await asyncio.sleep(30)
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def schedule_online_status_maintenance():
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"""
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调度在线状态维护任务
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"""
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task = asyncio.create_task(start_online_status_maintenance_task())
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return task
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