121 lines
2.8 KiB
Python
121 lines
2.8 KiB
Python
from __future__ import annotations
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from datetime import datetime
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def unix_timestamp_to_windows(timestamp: int) -> int:
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"""Convert a Unix timestamp to a Windows timestamp."""
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return (timestamp + 62135596800) * 10_000_000
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def camel_to_snake(name: str) -> str:
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"""Convert a camelCase string to snake_case."""
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result = []
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last_chr = ""
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for char in name:
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if char.isupper():
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if not last_chr.isupper() and result:
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result.append("_")
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result.append(char.lower())
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else:
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result.append(char)
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last_chr = char
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return "".join(result)
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def snake_to_camel(name: str, use_abbr: bool = True) -> str:
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"""Convert a snake_case string to camelCase."""
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if not name:
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return name
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parts = name.split("_")
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if not parts:
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return name
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# 常见缩写词列表
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abbreviations = {
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"id",
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"url",
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"api",
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"http",
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"https",
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"xml",
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"json",
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"css",
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"html",
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"sql",
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"db",
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}
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result = []
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for part in parts:
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if part.lower() in abbreviations and use_abbr:
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result.append(part.upper())
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else:
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if result:
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result.append(part.capitalize())
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else:
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result.append(part.lower())
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return "".join(result)
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def snake_to_pascal(name: str, use_abbr: bool = True) -> str:
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"""Convert a snake_case string to PascalCase."""
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if not name:
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return name
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parts = name.split("_")
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if not parts:
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return name
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# 常见缩写词列表
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abbreviations = {
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"id",
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"url",
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"api",
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"http",
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"https",
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"xml",
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"json",
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"css",
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"html",
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"sql",
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"db",
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}
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result = []
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for part in parts:
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if part.lower() in abbreviations and use_abbr:
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result.append(part.upper())
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else:
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result.append(part.capitalize())
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return "".join(result)
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def are_adjacent_weeks(dt1: datetime, dt2: datetime) -> bool:
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y1, w1, _ = dt1.isocalendar()
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y2, w2, _ = dt2.isocalendar()
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# 按 (年, 周) 排序，保证 dt1 <= dt2
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if (y1, w1) > (y2, w2):
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y1, w1, y2, w2 = y2, w2, y1, w1
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# 同一年，周数相邻
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if y1 == y2 and w2 - w1 == 1:
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return True
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# 跨年，判断 y2 是否是下一年，且 w2 == 1，并且 w1 是 y1 的最后一周
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if y2 == y1 + 1 and w2 == 1:
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# 判断 y1 的最后一周是多少
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last_week_y1 = datetime(y1, 12, 28).isocalendar()[1] # 12-28 保证在最后一周
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if w1 == last_week_y1:
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return True
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return False
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def are_same_weeks(dt1: datetime, dt2: datetime) -> bool:
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return dt1.isocalendar()[:2] == dt2.isocalendar()[:2]
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